k^2=121/25

Solution for k^2=121/25 equation:

k^2=121/25

We move all terms to the left:

k^2-(121/25)=0

We add all the numbers together, and all the variables

k^2-(+121/25)=0

We get rid of parentheses

k^2-121/25=0

We multiply all the terms by the denominator


k^2*25-121=0

Wy multiply elements

25k^2-121=0

a = 25; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·25·(-121)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*25}=\frac{-110}{50}
=-2+1/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*25}=\frac{110}{50}
=2+1/5
$